Question

In a building there are 10 cylindrical pillars. The radius of each pillar is 14m and height is 5m.

Find the cost of painting the curved surface area of all pillars at the rate of Rs.25 per m2

.​

Answer 1

Step-by-step explanation:

Given, r=63 cm, h=15 m, h=15×100 cm

Curved surface area =2πrh

=2× 22/7×63×15×100

=594000cm

Total number of pillars =4

CSA of one pillar =594000

CSA of 4 pillars =594000×4=2376000 = 237.6m

Answer 2

Answer:

$csa \: of \: cylinder \: = 2\pi \: rh \\ = 2 \times \frac{22}{7} \times 14 \times 5 \\ = 2 \times 22 \times 2 \times 5 \\ = 44 \times 10 \\ = 440 {m}^{2}$

$cost \: of \: painting \: one \: {m}^{2} \: = 25 \\ cost \: of \: painting \: one \: pillar \: = 440 \times 25 = 11000rs$

$cost \: of \: painting \: one \: pillar = 11000rs \\ cost \: of \: panting \: 10 \: pillars \: = 11000 \times 10 \\ = 110000rs$

$please \: mark \: as \: brainliest \: please \: help \: me$