in a building there are 4 cylindrical pillars .the radius of each pillar is 21cm and height is 5m .find the curved surface area of four pillars
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8
Given
Radius = 21 cm.
Height = 5 m = 500 cm.
Curved Surface area of one pillar = 2 × π × radius × height
= 2 × 22/7 ×21 × 500
= 66000 cm^2 = 6.6 m^2
Hence ,Curved Surface area of 4 such Pillars = 4 × 6.6
= 26.4 m^2.
PEACE
Radius = 21 cm.
Height = 5 m = 500 cm.
Curved Surface area of one pillar = 2 × π × radius × height
= 2 × 22/7 ×21 × 500
= 66000 cm^2 = 6.6 m^2
Hence ,Curved Surface area of 4 such Pillars = 4 × 6.6
= 26.4 m^2.
PEACE
Answered by
4
CSA of cylinder is 2πrh ×4
2×22/7×21×5×100×4
=66000×4
=264000
2×22/7×21×5×100×4
=66000×4
=264000
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