In a building there are some humans (2 legs each), thrice as many dogs (4 legs each), and some number of spiders (8 legs each). If there are 50 legs in total, how many spiders are there?
Answers
Given : there are some humans(2 legs each) thrice as many dogs (4 legs each)and some number of spiders(8legs each)
To find : how many spiders are there
Solution:
Let day dogs = D
Number of legs of Dogs = 4D
Human thrice as many Dogs
=> Human = 3D
=> Legs of Human = 2 * 3D = 6D
Total number of legs of Dogs & Human = 4D + 6D = 10D
Let say Spider = S
Number of spider legs = 8S
8S + 10D = 50
8S must end with 0 as all other terms are ending with zero
Hence Either
Spider = 0 or 5
as its given some spiders hence we ignore 0 ,
Spider = 5 , Dogs = 1 Human = 3
5 Spiders are there
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