In a bulb factory, machines a, b and c manufacture 60%, 30% and 10% bulbs respectively. 1%, 2% and 3% of the bulbs produced respectively by a, b and c are found to be defective. A bulb is picked up at random from the product and is found to be defective. Find the probability that this bulb was produced by the machine a.
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Ahoy Matey !!
Here's your answer,
Let's assume that there are 100 bulbs being produced in the factory.
So, bulbs produced by machine 'a' = 60 bulbs Number of defective bulbs produced by machine 'a' = 1% of 60
= 1÷100 × 60
= 0.6 bulbs
Probability of getting a defective bulb produced by machine 'a'
= No. of favourable outcomes ÷ Total no. of outcomes
= 0.6÷100
=0.006 (Answer)
.
.
Hope it helps :-)
Here's your answer,
Let's assume that there are 100 bulbs being produced in the factory.
So, bulbs produced by machine 'a' = 60 bulbs Number of defective bulbs produced by machine 'a' = 1% of 60
= 1÷100 × 60
= 0.6 bulbs
Probability of getting a defective bulb produced by machine 'a'
= No. of favourable outcomes ÷ Total no. of outcomes
= 0.6÷100
=0.006 (Answer)
.
.
Hope it helps :-)
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