Question

In a bus (2x+5) passengers bought 50 paise tickets and (3x-2) bought 75 paise tickets. if the bus was 48 seater and was just full , find rhe number of passengees for each category.

Answer 1

Answer: There are 23 passengers buying 50 paise tickets and 25 passengers buying 75 paise tickets.

Step-by-step explanation:

Number of passengers who bought 50 paise tickets = 2x+5

Number of passengers who bought 75 paise tickets = 3x-2

Since we have given that

Total number of passengers = 48

According to question, it becomes,

$2x+5+3x-2=48\\\\5x+3=48\\\\5x=48-3\\\\5x=45\\\\x=\dfrac{45}{5}\\\\x=9$

So, Number of passenger who bought 50 paise tickets = 2x+5=2×9+5=18+5=23

Number of passengers who bought 75 paise tickets = 3x-2=3×9-2=27-2=25.

Thus, there are 23 passengers buying 50 paise tickets and 25 passengers buying 75 paise tickets.

Answer 2

Answer: There are 23 passengers buying 50 paise tickets and 25 passengers buying 75 paise tickets.

Step-by-step explanation:

Number of passengers who bought 50 paise tickets = 2x+5

Number of passengers who bought 75 paise tickets = 3x-2

Since we have given that

Total number of passengers = 48

According to question, it becomes,

So, Number of passenger who bought 50 paise tickets = 2x+5=2×9+5=18+5=23

Number of passengers who bought 75 paise tickets = 3x-2=3×9-2=27-2=25.

Thus, there are 23 passengers buying 50 paise tickets and 25 passengers buying 75 paise tickets.