In a.c.circuit,the current and voltage are given by i=5coswt and V=2oosinwt.power loss in the circuit is
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A/C to question,
i = 5cosωt
i = 5sin(ωt + π/2) [ we know , sin(90+A) = cosA ]
V = 200sinωt
V = 200sin(ωt + 0)
hence, phase difference between I and V is
Φ = π/2 - 0 = π/2
now, Power loss in circuit = Vi.cosΦ
where V and I are sinusoids rms values, Φ is the phase difference between Voltage and current.
because Φ = π/2 => cosΦ = 0
so, Power loss in circuit = 0
i = 5cosωt
i = 5sin(ωt + π/2) [ we know , sin(90+A) = cosA ]
V = 200sinωt
V = 200sin(ωt + 0)
hence, phase difference between I and V is
Φ = π/2 - 0 = π/2
now, Power loss in circuit = Vi.cosΦ
where V and I are sinusoids rms values, Φ is the phase difference between Voltage and current.
because Φ = π/2 => cosΦ = 0
so, Power loss in circuit = 0
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