Question

in A.c circuit, the current and voltage by i=5 cos wt, and V=200 sin wt respectively. power loss in the circuit is -

Answer 1

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Answer 2

The power loss in the circuit is 0.

Explanation:

Current in AC circuit, $I=5\cos\omega t$

Voltage in AC circuit, $V=200\sin\omega t$

We need to find the power loss in the circuit. We know that :

$\sin(90+\theta)=\cos\theta$

We can write the current as :

$I=5\ \sin(90+\omega t)$

Voltage is given by :

$V=200\ \sin(\omega t+0)$

The phase difference between voltage and current is :

$\phi =90^{\circ}-0=90^{\circ}$

The power loss in the circuit is given by :

$P=VI\cos\phi\\\\P=VI\cos(90)\\\\P=0$

Since, cos(90) is 0, so the power loss in the circuit is 0. Hence, this is the required solution.

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