Question

In a cage, there are sparrows, parrots and doves in the ratio 3:7:5. If the number of parrots was more than the
number of sparrows by a multiple of both 9 and 7, what is the minimum number of birds in the cage?
945
630
238
None of these
​

Answer 1

Answer:

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semi-circle. What is the radius of the semi-circle

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Step-by-step explanation:

In a cage, there are sparrows, parrots and doves in the ratio 3:7:5. If the number of parrots was more than the

number of sparrows by a multiple of both 9 and 7, what is the minimum number of birds in the cage?

945

630

238

None of these

Answer 2

Answer:

If three kinds of birds are taken be 3k,7k and 5k respectively, then 7k−3k=63p (where p is any positive integer).

As the number is a multiple of both 9 and 7, it has to be multiple of 63.

⇒k=63p4

Minimum value of p for which k is a natural number is 4.

Thus, k=63.

Hence, the number of birds =15k= 945