Question

in a calendar a square of four numbers is marked .The sum of the numbers is 80 .what are the numbers?

Answer 1

let the number be
$4 {x}^{2} \\ 4 {x}^{2} = 80 \\ {x}^{2} = \frac{80}{4} \\ {x}^{2} = 20 \\ x = \sqrt{20} \\ x = \sqrt{2 \times 2 \times 5} \\ x = 2 \times 5 \\ x = 10$
Hope it helps