Question

in a calender, a square of foure numbers is marked. the sum of the number is 40.what are the number​

Answer 1

$\huge⚘ \bf \ \red{Answer}$

80 = (x) + (x+1) + (x+7) + (x+8)

Combining like terms, it follows that…

80 = 4x + 16

Subtracting 16 from both sides gives us…

64 = 4x

Dividing by 4 on both sides results in…

x = 16

Now that we have our x value, we can simply add 1, 7, and 8, respectively, to 16 to get our solution:

The set of numbers is [16, 17, 23, 24]