Question

In a calorimeter, 20 g of ice absorbs heat with an enthalpy of fusion of 334 J/g. What is the heat absorbed?

Answer 1

Answer : The heat absorbed is, 6680 J

Explanation :

Formula used :

$Q=m\times \Delta H_{fusion}$

where,

Q = heat absorbed = ?

m = mass of ice = 20 g

$\Delta H_{fusion}$ = enthalpy of fusion = 334 J/g

Now put all the given values in the above formula, we get the heat absorbed.

$Q=20g\times 334J/g$

$Q=6680J$

Therefore, the heat absorbed is, 6680 J