in a camp there is enough food to feed certain number of people for 50 days if 30 more people join the camp after 10 days the food will last for 25 days how many people were earlier present in the camp
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To understand in an easier way
Let us assume that 100 soldiers can eat ration food(x) in 10 days
So for one day the food that they eaten is x/10
So for two days 2*(x/10)=x/5
So remaining food is x-(x/5)=4x/5
Let this food will be eat by 160 soldiers in ‘d’ days
If one soldier can eat 1/(10*100) th food per day then for
160 soldiers and ‘d’ days =160*d*1/(10*100)=d*4/25 th of food
This must be equal to remaining 4x/5 food
Therefore d*4/25=4/5=> d=5 days
Hope you understood, comment below if you have any doubts
Let us assume that 100 soldiers can eat ration food(x) in 10 days
So for one day the food that they eaten is x/10
So for two days 2*(x/10)=x/5
So remaining food is x-(x/5)=4x/5
Let this food will be eat by 160 soldiers in ‘d’ days
If one soldier can eat 1/(10*100) th food per day then for
160 soldiers and ‘d’ days =160*d*1/(10*100)=d*4/25 th of food
This must be equal to remaining 4x/5 food
Therefore d*4/25=4/5=> d=5 days
Hope you understood, comment below if you have any doubts
mukeshalan:
your answer is wrong
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4
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