Math, asked by devanshimadam4467, 3 days ago

In a camp with 45 athletes, there is enough food to last for 25 days. After 5 days, 15 more athletes join the camp. For how long will the food last now? ( Use inverse variation method).​

Answers

Answered by AyuDutta
0

Step-by-step explanation:

Let’s assume that the athletes eat food packets three times a day

3 meals a day

3 meals a day25 days

3 meals a day25 days45 athletes

3 meals a day25 days45 athletes3x25x45 = 3375 food packets

3 meals a day25 days45 athletes3x25x45 = 3375 food packetsIn 5 days they used following packets

3 meals a day25 days45 athletes3x25x45 = 3375 food packetsIn 5 days they used following packets5 days x 3 meals x 45 athletes = 675 meals

3 meals a day25 days45 athletes3x25x45 = 3375 food packetsIn 5 days they used following packets5 days x 3 meals x 45 athletes = 675 mealsSo 675 meals have been used

3 meals a day25 days45 athletes3x25x45 = 3375 food packetsIn 5 days they used following packets5 days x 3 meals x 45 athletes = 675 mealsSo 675 meals have been usedSo the camp is left with 3375–675=2700 meals

3 meals a day25 days45 athletes3x25x45 = 3375 food packetsIn 5 days they used following packets5 days x 3 meals x 45 athletes = 675 mealsSo 675 meals have been usedSo the camp is left with 3375–675=2700 mealsNow 15 more athletes join, that’s total of 60 athletes (45+15)

3 meals a day25 days45 athletes3x25x45 = 3375 food packetsIn 5 days they used following packets5 days x 3 meals x 45 athletes = 675 mealsSo 675 meals have been usedSo the camp is left with 3375–675=2700 mealsNow 15 more athletes join, that’s total of 60 athletes (45+15)So 60 athletes consume total of 180 meals in a day. (Calculating 3 meals a day)

3 meals a day25 days45 athletes3x25x45 = 3375 food packetsIn 5 days they used following packets5 days x 3 meals x 45 athletes = 675 mealsSo 675 meals have been usedSo the camp is left with 3375–675=2700 mealsNow 15 more athletes join, that’s total of 60 athletes (45+15)So 60 athletes consume total of 180 meals in a day. (Calculating 3 meals a day)2700/180

3 meals a day25 days45 athletes3x25x45 = 3375 food packetsIn 5 days they used following packets5 days x 3 meals x 45 athletes = 675 mealsSo 675 meals have been usedSo the camp is left with 3375–675=2700 mealsNow 15 more athletes join, that’s total of 60 athletes (45+15)So 60 athletes consume total of 180 meals in a day. (Calculating 3 meals a day)2700/180Thats 15. So the remaining food will last 15 days

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