In a capillary, water rises upto height 10
cm as shown in figure and height of capillary
is 15 cm. If suddenly gravity become twice then
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Answer:
The height h through which a liquid will rise in a capillary tube of radius r is given by
h=
rρg
2Scosθ
where S is the surface tension, ρ is the density of the liquid and θ is the angle of contact.
For identical capillary tubes and two liquids ( water '1' & mercury '2')
h
2
h
1
=
rρ
1
g
2S
1
cosθ
1
×
2S
2
cosθ
2
rρ
2
g
⇒
h
2
h
1
=
ρ
1
S
1
cosθ
1
×
S
2
cosθ
2
ρ
2
⇒
S
2
S
1
=
h
2
h
1
×
cosθ
1
cosθ
2
×
ρ
2
ρ
1
⇒
S
2
S
1
=
−3.42
10
×
cos0
∘
cos135
∘
×
13.6
1
⇒
S
2
S
1
=
−3.42
10
×
1
−0.707
×
13.6
1
⇒
S
2
S
1
=0.152≈
6.5
1
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