Question

In a car lift, a force F, acts on a smaller piston of radius 5 cm. the radius of the large piston is
15 cm. Mass of the car to be lifted up is 1350 kg Calculate the minimum value of Fı.
Ans. 150 kg wt​

Answer 1

Explanation:

HERE IS YOUR ANSWER!

From pascal’s law

P

1

=P

2

A

1

F

1

=

A

2

F

2

πr

1

2

F

1

=

πr

2

2

F

2

F

1

=

r

2

2

F

2

r

1

2

F

1

=

(15×10

−2

)

2

1350×9.8×(5×10

−2

)

2

F

1

=1470N

F

1

=1.47×10³ N

HOPE IT HELPS YOU !

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