In a car lift compressed air exerts a force f1 on a small piston having a radius of 5 cm.this pressure is transmitted to a second piston of radius 15 cm.if the mass of the car to be lifted is 1350 kg what is f1?what is the pressure necessary to accomplish this task?take g=9.8ms^-2
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Answered by
242
According to Pascal's law, Pressure is transmitted equally and undiminished through out the fluid.
P1=P2
F1/A1=F2/A2
F1= (A1/A2 ) F2
=[π(5 x10⁻²m)²/π(15x10⁻²m)² ](1350Nx9.8m/s2)
=1470N
=1.5 x 10³ N
The air pressure that will produce this force
P=F1/A1
=1.5x10³N/π(5x10⁻²)² m
=1.9 x 10⁵ Pa
This is almost the double of atmospheric pressure.
P1=P2
F1/A1=F2/A2
F1= (A1/A2 ) F2
=[π(5 x10⁻²m)²/π(15x10⁻²m)² ](1350Nx9.8m/s2)
=1470N
=1.5 x 10³ N
The air pressure that will produce this force
P=F1/A1
=1.5x10³N/π(5x10⁻²)² m
=1.9 x 10⁵ Pa
This is almost the double of atmospheric pressure.
Answered by
70
Answer: we get answer as 1.47*10^3
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