Physics, asked by madhupenta77, 1 month ago

. In a car race car A takes a time of ‘t’ sec less than car B at the finish and passes the
finishing point with a velocity ‘V’ more than car B. Assuming the cars starts from rest
and travel with constant accelerations a1 & a2 respectively. Show that V = √ܽa1a2t
.

Answers

Answered by manojchauhanma2
1

Answer:

Formula Used: Equations of motion used in the solution are. where u is the initial velocity, v is the final velocity, a is acceleration, t is time taken and S is the total distance covered by the moving body. Therefore, the correct answer is option D.

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