Physics, asked by zzassergaming123, 8 months ago

In a car race, car A takes time t less than car B and passes the finishing point with a velocity v more than the velocity with which car B passes the point, Assuming that the cars start from rest and travel with constant accelerations a1 and a2 respectively, the value of \frac{v}{t} is

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Answered by svenkatanaveen06
1

11th

Physics

Motion in a Straight Line

Problems on Equation of Motion

In a car race, car A take...

PHYSICS

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Asked on October 15, 2019 by

Prabhjit Honey

In a car race, car A takes a time t less than car B at the finish and passes the finishing point with speed v more than that of the car B. Assuming that both the cars starts from rest and travel with constant accelerations a

1

and a

2

respectively. So, the value of v will be :

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ANSWER

Consider that A takes t

1

second, then according to the given problem, B will take (t

1

+t) seconds. Further let v

1

be the velocity of B at finishing point, then velocity of A will be (v

1

+v). Writing equations of motion for A and B

v

1

+v=a

1

t

1

....(i)

v

1

=a

2

(t

2

+t) ....(ii)

From equations (i) and (ii), we get

v=(a

1

−a

2

)t

1

−a

2

t .....(iii)

Total distance travelled by both the cars is equal

S

A

=S

B

2

1

a

1

t

1

2

=

2

1

a

2

(t

1

+t)

2

⇒t

1

=

a

1

a

2

a

2

t

Substituting this value of t

1

in equation (iii), we get

v=(

a

1

a

2

)t

Answered by amulya43
1

Which book's question?

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