Physics, asked by kaushalkaushal5724l, 5 hours ago

In a car race, car A takes time 't' less than the car B and passes the finishing point with a velocity 'v' more than the velocity with which the car B passes the point. Assuming that the cars start from rest travels with constant acceleration a,and ay, then ( where t, and t, are time taken by the cars A and B to completed the race)​

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Answered by koushikTopper
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Answer:

Explanation:

In a car race, car A takes a time t less than car B at the finish and passes the finishing point with speed v more than that of car B. Assuming that both the cars start from rest and travel with constant acceleration a1 and a2 respectively. So, the value of v will be : A. (√a1a2)tB. (√a2a1)tC.

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