Question

In a Carnot engine efficiency is 40% at hot reservoir
temperature T. For efficiency 50%, what will be the
temperature of hot reservoir?
(a) T (b) 2/3 T
(c) 4/5 T (d)6/5 T

Answer 1

Answer:

The efficiency, η=heatinputworkdone=QW

η=1−T1T2

where, T2= temperature of sink

and T1= temperature of hot reservoir

10040=1−T1T2

T1T2=0.6⇒T2=0.6T1

Now, 10050=1−T1′T2⇒T1′T2=0.5

T1′0.6