In a cartesian plane, if the co-ordinates of a triangle ABC with A (a, 3), B (5, b) and C (a, b) are in a relation such that 3 times of abscissa is equal to 2 times of its ordinate. Write the co-ordinate of triangle ABC . Hence also write the co-ordinates of image of ABC . With respect to x-axis
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(i) Distance of A from the Y-axis = OL = -6 units
Distance of A from the X-axis = AL = 5 units
Hence, the coordinates of A are (-6,5).
(ii) Distance of B from the Y-axis = OM = 5 units
Distance of B from the X-axis = BM = 4 units
Hence, the coordinates of B are (5,4).
(iii) Distance of C from the Y-axis = ON = -3 units
Distance of C from the X-axis = CN = 2 units
Hence, the coordinates of C are (-3,2).
(iv) Distance of D from the Y-axis = OP = 2 units
Distance of D from the X-axis = DP = -2 units
Hence, the coordinates of D are (2,-2).
(v) Distance of E from the Y-axis = OL = -1 units
Distance of E from the X-axis = AL = -4 units
Hence, the coordinates of E are (-1,-4).
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