Physics, asked by harrybhangu7790, 2 months ago

 In a catalytic experiment involving Haber's process, N₂(g)+H₂(g) −−−−−> 2NH₃(g), the rate of reaction was measured as : Rate = d[NH₃]/dt =2.0*10⁻⁴ Ms⁻¹. If there were no side reaction, what was the rate of reaction expressed in terms of N₂ ? 

(A)1*10⁻⁴ M s⁻¹

(B) 4*10⁻⁴ M s⁻¹

(C) 5*10⁻3 M s⁻¹

(B) 1*10⁻3 M s⁻¹​

Answers

Answered by simran12363
1

Answer:

option number d

1*10-3Ms-1

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