Chemistry, asked by sunil91289, 11 months ago

In a catalytic reaction involving the formation of ammonia by Haber's process N2, + 2H2, + 2NH3, the rate of apperance
of NH, was measured as 2.5 x 10-4 mol L-S-. The rate of disappearance of H2, will be -
(1) 2.5 x 10-4 mol L-1 S-1
(2) 1.25 x 10-4 mol L-1 S-1
(3) 3.75 x 10-4 mol L-IS-1
(4) 5 x 10-4 mol L-1 S-1

Answers

Answered by GMOJASRAUT
1

Answer:

The catalytic reaction which is involving the formation of ammonia through the Haber's process N2+3H2 → 2N3.

Appearance rate of NH3 was measured as 2.5*10^ -4 mole L^-1 S^-1.

   -1/3dH2/dt = -1/2dNH2/dt

   -dH2/dt = 1/2x3x2.5x10-4

   -dH2/dt = 3.75 x 10-4 mol L-1S-1

The rate of the disappearance will be based on Haber's process is 3.75 x 10-4 mol L-1S-1.

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Explanation:

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