In a CE transistor amplifier, the audio signal voltage across the collector resistance of 2kOmega is 2V. If the base resistance is 1kOmega and the current amplification of the transistor is 100, the input signal voltage is
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For a CE transistor amplifier, the audio signal voltage across the collector resistance of 2k Omega is 2V. Suppose the current amplification factor of the transistor is 100. The value of R_(B) in series with V_(BB) supply of 2V, if the DC base current has to be 10 times the signal current is. ∴RB=(2-0.6)0.10=14kΩ.
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20m V is ur correct answer dear please
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