Question

In a CE transistor amplifier, the audio signal voltage across the collector resistance of 2k Ω is 2V. If the base resistance is 1k Ω and the current amplification of the transistor is 100, the input signal voltage is(a) 0.1 V(b) 1.0 V(c) 1 mV(d) 10 mV

Answer 1

here is ur answer ....☺

Answer 2

Answer:

d) 10mV

Explanation:

Voltage = Rc = 2 kΩ = 2 × 10³Ω (Given)

Base resistance = Rb = 1 kΩ (Given)

V₀ = 2V

Input voltage (Vi) = ?

Thus, using the equation -

β = Ic / Ib = 100

V₀ = IcRc = 2 V

Ic = 2 / Rc = 2 / 2 × 10³ Ω

= 10⁻³ A = 1 mA

Calculating the base current -

=  Ib = Ic / β

= 10⁻³ / 100

= 10 × 10⁻⁶ A

= 10 μA

Input resistance voltage = Vi = Rb / Ib

= 1 × 10³ × 10 × 10⁻⁶

= 10mV

Thus, the input signal voltage is 10mV,