Question

In a ceiling fan, each blade rotates in a circle of radius 05 m. If the fan makes 2 rotations per second and the vertical component of the earths magnetic field is 8 105 t, calculate the emf induced between the inner and outer ends of each blade.

Answer 1

The emf induced between the inner and outer ends of each blade is $1.26 \times 10^{-4}$ V.

Explanation:

As we know that the EMF induced due to rotation of conductor in constant magnetic field is given as

$EMF = \frac{1}{2}B\omega L^2$

here we know that

$\omega = 2\pi f$

$\omega = 2\pi(2)$

$\omega = 4\pi rad/s$

$B = 8 \times 10^{-5} T$

$L = 0.5 m$

now we have

$EMF = \frac{1}{2}(8\times 10^{-5})(4\pi)(0.5)^2$

$EMF = 1.26 \times 10^{-4} V$

#Learn

Topic : Induced Motional EMF

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