In a certain Algebra 2 class of 21 students, 7 of them play basketball and 8 of them play baseball. There are 11 students who play neither sport. What is the probability that a student chosen randomly from the class plays both basketball and baseball?
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Answered by
3
Answer:
5/21
Step-by-step explanation:
21-11 = 10 students who play any sport.
7+8=15.
15-10= 5 number of students playing both sports.
Probability =5/21
Answered by
0
Answer = 5/21
21-11 = 10 students who play any sport.
7+8=15.
15-10= 5 number of students playing both sports.
Probability =5/21
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