Question

In a certain Algebra 2 class of 26 students, 10 of them play basketball and 5 of them play baseball. There are 3 students who play both sports. What is the probability that a student chosen randomly from the class plays basketball or baseball?

Answer 1

Answer:

$\frac{6}{13} \: is \: your \: answer$

Step-by-step explanation:

K=basketball, S= baseball

10K

5S

3 K & S

26 total

P(K) = 10/26, P(S) = 5/26 P(K^S) = 3/26

P(K v S) = P(K) + P(S) - P(K^S) = 10/26 + 5/26 - 3/26 = 12/26 = 6/13

Probability of randomly getting a student who plays either basketball or baseball = 6/13