In a certain Algebra 2 class of 26 students, 10 of them play basketball and 5 of them play baseball. There are 3 students who play both sports. What is the probability that a student chosen randomly from the class plays basketball or baseball?
Yes it does
but I don't have too many pwoints here so I will ask from the other I'd
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There are 3 students who play both sports. What is the probability that a student chosen randomly from the class plays basketball or baseball?
BRO TUMHARI DUSRI ID KA NAME KYA HAI?
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Answer:
K=basketball, S= baseball
10K
5S
3 K & S
26 total
P(K) = 10/26, P(S) = 5/26 P(K^S) = 3/26
P(K v S) = P(K) + P(S) - P(K^S) = 10/26 + 5/26 - 3/26 = 12/26 = 6/13
Probability of randomly getting a student who plays either basketball or baseball = 6/13
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