Question

In a certain Algebra 2 class of 28 students, 11 of them play basketball and 13 of them play baseball. There are 11 students who play neither sport. What is the probability that a student chosen randomly from the class plays both basketball and baseball?

Answer 1

Answer:

1/4

Step-by-step explanation:

28-11 = 17

13+11=24-17 = 7

7/28 =1/4

Answer 2

The required probability is $\dfrac{1}{7}$

Step-by-step explanation:

Since we have given that

Number of students = 28

Number of students play basketball = 11

Number of students play baseball = 13

Number of students neither play sports = 11

so, Number of students who play both would be

$28-(11+13)\\\\=28-24\\\\=4$

So, the probability of getting played both games would be

$\dfrac{4}{28}=\dfrac{1}{7}$

Hence, the required probability is $\dfrac{1}{7}$

# learn more:

In a certain Algebra 2 class of 28 students, 11 of them play basketball and 13 of them play baseball. There are 11 students who play neither sport. What is the probability that a student chosen randomly from the class plays both basketball and baseball?

https://brainly.in/question/16269050