Question

In a certain Algebra 2 class of 30 students, 14 of them play basketball and 10 of them play baseball. There are 14 students who play neither sport. What is the probability that a student chosen randomly from the class plays both basketball and baseball?

Answer 1

Basketball =A Baseball =B
n(AUB)= 30-14=16
n(A and B ) = 14+10-16 =8
P(A and B)= 8/30