Question

In a certain AP times the 5th term is equal to 8 times the 8th term then its 13th term is equal to

Answer 1

Answer:

let of the AP

first term= a

common difference=d

ATQ

5[a+(5-1)d]=8[a+(8-1)d]

5(a+4d)=8(a+7d)

5a + 20d = 8a + 56d

3a = 36d

a= -12d

Now 13th term

a+(13-1)d

=-12d+12d

=0

hence,proved

=>I hope my answer will help you

STAY AT HOME AND STAY SAFE

step-by-step explanation:

Answer 2

5th term = a + 4d

8th term = a + 7d

now,

5(a + 4d) = 8(a + 7d)

5a + 20d = 8a + 56d

3a + 36d = 0

3(a + 12d)=0

a + 12d = 0

Therefore, the 13th term is 0.