Question

In a certain Bohr orbit, the is - 4.9 ev. The and kinetic energy and potential energy in that orbit respectively is
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Answer 1

Answer:

Potential Energy, PE=−kZe  

2

/r, whereas KE=1/2×mv  

2

.

According to Bohr's Model, mv  

2

/r=kZe  

2

/r  

2

, therefore 1/2×mv  

2

=kZe  

2

/2r.  

KE=−PE/2.

TotalEnergy=−4.9

K.E+PotentialEnergy=TotalEnergy

K.E=4.9ev=(−totalEnergy)

P.E=2[totalEnergy]=−9.8ev

Explanation: