Math, asked by ritika7992s, 6 months ago

In a certain box there are coins of 50 paise, 25 paise and 20 paise in the ratio of 2:3;5
If their total is 110, find how many coins are there of each type?​

Answers

Answered by namannara7
1

ANSWER:

Variety of coins are --

_50 paise

_25 paise

_20 paise

First of all convert 110 ruppes into paise that will equals to 11000paise

RATIO OF THE QUANTITY- 2:3:5

=2x + 3x + 5x =11000

=10x = 11000

= x = 11000 ÷ 10

= x=1100

PUTTING VALUE OF X

50 PAISE ARE IN RATIO 2x

SO, 2×1100 = 2200 PAISE

SIMILARLY,

25 PAISE ARE IN RATIO 3x

3x = 1100×3 = 3300 PAISE

20 PAISE ARE IN RATIO 5x

5x = 5×1100= 5500 PAISE

IF WE DIVIDE THE VALUES WITH THEIR RESPECT COINS WE WOULD GET NUMBER OF COINS

2200÷50 = 44

SO THERE ARE 44 COINS OF 50 PAISE

3300÷25 = 132

SO THERE ARE 132 COINS OF 25 PAISE

5500÷20 = 275

SO THERE ARE 275 COINS OF 20 PAISE

PLEASE MARK ME AS BRAINLEIEST

Similar questions