Math, asked by hemamalininr, 7 months ago

In a certain code language
AVIATOR = 103, FIXTURE = 86, then how DIVERSE is written in that language ?
(1) 102
(2) 107
(3) 105
(4) 106

Answers

Answered by yashasvijain8014
2

Step-by-step explanation:

A V I A T O R

1+22+9+1+20+15 + 18

= 22+10+21+15+18

= 30+21+33

= 51+33

= 84

103 - 84

= 19

F I X T U R E

6+9+24+20+21+18+5

= 15+44+21+23

= 59+44

= 103

103 - 86

= 19

D I V E R S E

4+9+22+5+18+19+4

= 13+22+23+23

= 35+46

= 81

81 + 19 = 100

nearest is 102

so answer should be (1) 102

most right answer is 100.

hope it helps!

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