Math, asked by madmadgenius, 8 months ago

in a certain commercial bank, customers withdraw cash through one of the two tellers at a counter. on average, one teller takes 3 min while the other teller takes 5 min to serve a customer. if the two tellers start to serve customers at the same time, find the shortest time each takes to serve 200 customers?

Answers

Answered by jaya362238
3

Step-by-step explanation:

Suppose a small bank has only one teller. Customers take an average of 10 minutes to serve and they arrive at the rate of 5.8 per hour. What will the expected waiting time be? What happens if you add another teller?

We assume customer arrivals and customer service times are random (details later). With only one teller, customers will have to wait nearly five hours on average before they are served. But if you add a second teller, the average waiting time is not just cut in half; it goes down to about 3 minutes. The waiting time is reduced by a factor of 93x.

Answered by xiulaybaeksoo
12

Answer:

lcm of 3 and 5  which will be 15 then       the by knowing how many the first teller deals with per 15 min you do ...15 divide by 3 which is 5 .......n then the 2nd teller u divide 15 by 5 which is 3 so the first teller =5 peeps per 15 min while th 2nd teller 3 peeps per min so u add the 5+3=8 .....then if 8 peeps take 15 mins what about 200 peeps? 375 mins or 6 hrs 15 mins                                                  

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