In a certain company, 20% of the men and 40% of the women attended the annual company picnic.If 35% of all the employees are men.What % of all the employee went to the picnic?
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#73097
Physics / Other
In a circular accelerator a proton is accelerated to an energy of
퐸
=
10
12
eV, as measured
in the
laboratory frame. If the rest energy of the proton is
퐸
0
=
10
9
eV, calculate
i) the
speed of the proton as measured in the laboratory frame
ii) the force that must be applied by the magnets in the accelerator to keep the
protons moving
at this speed in a circle of radius
푅
=
1000
m.
Solution
:
i)
The energy of the proton
퐸
=
푚
푐
2
√
1
−
푣
2
푐
2
=
퐸
0
√
1
−
푣
2
푐
2
Thus
푣
=
푐
√
1
−
(
퐸
0
퐸
)
2
푣
=
푐
√
1
−
(
10
9
10
12
)
2
=
0
.
9999995
푐
=
299999850
m
/
s
ii)
The Newton’s second law states
푚푎
=
퐹
Centripetal acceleration
푎
=
푣
2
푅
Thus
퐹
=
푚
푣
2
푅
퐹
=
1
.
67
×
10
−
27
×
299999850
2
1000
=
1
.
5
×
10
−
13
N
Answer
s
:
i)
0
.
9999995
푐
=
299999850
m
/
s
ii)
1
.
5
×
10
−
13
N
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