Question

In a certain electrolysis experiment 0.561 of zinc deposite in one cell containing znso4 solution. Calculate the mass of cu in another cell containing CuSo4 solun in a series with ZnSo4 cell. Given:- molar mass of Zn &Cu are 65.4 & 63.5 g. Resptly​

Answer 1

W = (A X I X t) ÷ (n x 96500)

W1 be mass of Zn and W2 be mass of Cu,

W1 = (A1 X I X t) ÷ (n1 x 96500)

0.561 = (65.4 x I X t) ÷ ( 2 x 96500) = (65.4 x I X t) ÷ 193000

(0.561 x 193000) ÷ 65.4 = I X t------------- equation 1

W2 = (A2 X I X t) ÷ (n2 x 96500) = {63.5 X [(0.561 x 193000) ÷ 65.4]} ÷ 193000 = 5.45g