Question

In a certain examination, the number of those who passed in paper I was 4times the number of those who failed. If there had been 20 less candidates for thepaper II and only four-fifth of the students had passed whereas the number ofstudents who failed is 4 less than that in paper I, then find the total of passed andfailed candidates in paper I would have been​

Answer 1

Given :- In a certain examination, the number of those who passed in paper I was 4times the number of those who failed. If there had been 20 less candidates for thepaper II and only four-fifth of the students had passed whereas the number of students who failed is 4 less than that in paper I, then find the total of passed and failed candidates in paper I would have been ?

Answer :-

Let number of students failed in paper I was x students .

so,

→ Number of students passed in paper I = 4x .

then,

→ Total students appear in paper I = 4x + x = 5x .

now, given that,

→ Students for paper II = 20 less = (5x - 20)

and,

→ Students passed = (4/5)th of (5x - 20) = (4/5) * 5 * (x - 4) = 4(x - 4) = (4x - 16) students .

also,

→ Number of students failed = 4 less than paper I = (x - 4) .

A/q,

→ (5x - 20) - (4x - 16) = (x - 4)

→ 5x - 4x - 20 + 16 = x - 4

→ x - 4 = x - 4 .

given data is not correct to solve the problem . Please check and post again .

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Answer 2

Answer:

it's cannot be determined