In a certain examination, the number of those who passed in paper I was 4times the number of those who failed. If there had been 20 less candidates for thepaper II and only four-fifth of the students had passed whereas the number ofstudents who failed is 4 less than that in paper I, then find the total of passed andfailed candidates in paper I would have been
Answers
Given :- In a certain examination, the number of those who passed in paper I was 4times the number of those who failed. If there had been 20 less candidates for thepaper II and only four-fifth of the students had passed whereas the number of students who failed is 4 less than that in paper I, then find the total of passed and failed candidates in paper I would have been ?
Answer :-
Let number of students failed in paper I was x students .
so,
→ Number of students passed in paper I = 4x .
then,
→ Total students appear in paper I = 4x + x = 5x .
now, given that,
→ Students for paper II = 20 less = (5x - 20)
and,
→ Students passed = (4/5)th of (5x - 20) = (4/5) * 5 * (x - 4) = 4(x - 4) = (4x - 16) students .
also,
→ Number of students failed = 4 less than paper I = (x - 4) .
A/q,
→ (5x - 20) - (4x - 16) = (x - 4)
→ 5x - 4x - 20 + 16 = x - 4
→ x - 4 = x - 4 .
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Answer:
it's cannot be determined