Math, asked by aaru11134, 5 months ago

in a certain examination the number of those who passed was 4 times a number of those who failed. If there had been 35 fewer candidates and 9 more had failed,candidates would have been 2 ratio 1 ,then the total number of candidates was ​

Answers

Answered by supernovalegend
5

Answer:

155

Step-by-step explanation:

Let number of failed students  = x  

number of passed students  = 4 x

total students  = x + 4 x = 5 x

If there had been 35 fewer students appeared and 9 more had failed,

total students  = 5 x − 35

number of failed students  = x + 9

passed students  = ( 5 x − 35 ) −( x + 9 ) = 4x − 44

( 4 x − 44 ) : ( x + 9) = 2 : 1

2 ( x + 9 ) = 4 x − 44

2 x + 18 = 4 x − 44

2 x = 62

x = 31

total students was  5 x = 5 X 31 =155

Answered by 1604630199orchidsedu
1

Answer:

155

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