in a certain experiment the count of bacteria was increasing at the rate of 2.5% per hour. initially,the count was 512000. find the bacteria at the end of 2 hours
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Answer:
537920 is the answer
Step-by-step explanation:
bacteria count after 1 hour
= 512000 + (512000*2.5/100)
= 512000 + 12800 = 524800
bacteria count after 2 hour
= 524800 + (524800*2.5/100)
= 524800 + 13120 = 537920
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