Question

in a certain experiment The Count of bacteria was increasing at the rate of 2.5 % per hour initially the count was 512000. Find the bacteria in the end of 2 hours

Answer 1

5/100 × 512000
= 25600
therefore,
512000 + 5% of 512000
= 512000 + 25600
= 537600

Therefore the count after 2hours is 537600

Answer 2

Answer:

${\huge{\underline{\underline{\sf{\blue{Solution :-}}}}}}$

Given :-

In a certain experiment The Count of bacteria was increasing at the rate of 2.5 % per hour initially the count was 512000. Find the bacteria in the end of 2 hours.

To find :-

Find the bacteria in the end of 2 hours.

Hence,

We have a count of bacteria is equal to 512000 rate at which bacteria are increasing is equal to 2.5 % per hour.

Therefore, count of bacteria at the end of

$2 \: hours = 512000 \: (1 + \frac{2.5}{100} ) ^{2}$

$= 512000 \: (1 + \frac{25}{1000} )^{2}$

$= 512000( \frac{41}{40} )^{2} = 537920$

Thus , The Count of bacteria at the end of 2 hours is 537920