Question

in a certain factory there are five workers A,B,C,Dand E,A can complete a work in 4minute,B in 5minutes,C in 6 minutes,D in 10 minutes and E in 12 minutes . The average number of units of work completed per worker per minute will be ?​

Answer 1

Solution :

Worker A can complete a work in 4 minuites .

Part of the work done by him in 1 min : ¼ th

Worker B can complete a work in 5 minuites .

Part of the work done by him in 1 min : ⅕ th

Worker C can complete a work in 6 minuites .

Part of the work done by him in 1 min : ⅙ th

Worker D can complete a work in 10 minuites .

Part of the work done by him in 1 min : ⅒ th

Worker E can complete a work in 12 minuites .

Part of the work done by him in 1 min : 1/12 th

Total average work done in a minuite :

=>( ¼ + ⅕ + ⅙ + 1/12 )/5

The LCM is 60

> [ 15 + 12 + 10 + 5]/[ 300 ]

=> 42/300

=> 7/100

Hence , 7/100 th of the work on an average is done in a minuite .

This is the required answer .

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