In a certain factory turning out optical lenses, there is a small
chance of 1/500 for any one lense to be defective. The lenses are supplied in packets of 10. Use poisson distribution to calculate the approximate number of packets containing no defective, one defective, two defective, three defective lenses respectively in a consignment of 20,000 packets. You are given that e-0.02 = 0.9802
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