Question

In a certain fraction the denominator is 4 less than the numerator if 3 is added to both the numerator and denominator the resulting fraction is equal to 9 by 7 find the original fraction ​

Answer 1

Answer:

15÷11

Step-by-step explanation:

Let numerator be x

Given fraction is x÷(x-4)

Therefore,

x+3÷(x-4+3)=9÷7

x+3÷x-1=9÷7

7x+21=9x-9

2x=30

x=15

Answer 2

Hey please mark the upper answer as Brainlist please