Math, asked by saxenashruti15, 1 year ago

In a certain language, "Delhi" Is coded as 4..And "Patna" is coded as 22.
How is "ASSAM" coded in that language??

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Answers

Answered by VishnuPriya2801
6

Answer:

according to the alphabets numbers

DELHI,PATNA

4,5,12,8,9-delhi

16,1,20,14,1-patna

L+(D-H)-(E-I) { Delhi}

=12-(4-8)-(5-9)

=12-4-4

=4

T+(P-N)-(A -A)

=20-(16-14)-0

=20+2=22

1,19,19,1,13-assam

S+(A -A) -(S -M )A

19+6=25

Answered by kodurupakarajendra
4

Answer:24

Step-by-step explanation:

"D" is the 4th letter of the English alphabet

So D=4

Similarly E=5 ,L=12, H=8, I=9

Now we need to add the numbers corresponding to the first three letters and then subtract the numbers corresponding to the last two letters or

4+5+12-(8+9)=4

Similarly for PATNA

P=16, A=1 ,T=20, N=14 ,A=1

Applying the same rule

We get

16+1+20-(14+1)=22

Now for ASSAM

A=1,S=19,S=19,A=1,M=13

1+19+19-(1+13)=24

Based on this logic I believe that 24 is the required answer.

Thank you for the question.

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