Question

In a certain language if MANGO is coded as OBNGO, score is coded as PDTRE, what will be the code for START in that language

Answer 1

Writing the alphabets in the sequential number-wise:

A(1), b(2), C(3),d(4), e(5), f(6), g(7), h(8),i(9),j(10),k(11), l(12), m(13), n(14), o(15), p(16), q(17), r(18), s(19), t(20), u(21), v(22), w(23), x(24), y(25), z(26)

M(13)   A(1)     N(14)    G(7)  O(15)

O(15)   B(2)   N(14)     G(7)   O(15)

S(19)    C(3)     O(15)    R(18)  E(5)

P(16)    D(4)     T(20)    R(18)  E(5)

Since, each time in the coding letters are getting increased by one, in the first case only first two letters got changed, in the second case first three letters got changed so, in the next schedule it might be get changed by 4.

It is a series following for the first letter is increasing by which number difference next time is decreasing by adding 1 with the difference, so, next time it will get increased by 1 from the difference of decreasing

In first case,

m(13) = o(15) (increase by 2)

In the second case,

s(19) = p(16) (decrease by 3)

So, in the third case, it might be,

s(19) = w(23) (increase by 4)

So, instead of 's' we are getting 'w'

For the second number its only getting increased by 1

in 1st case:

a(1) = b(2)  (increasing by 1)

in 2nd case:

c(3) = d(4) (increasing by 1)

So, in the 3rd case,it might be,

t(20) = u=(21) (increasing by 1)

So, instead of 't' we are getting 'u'

For the third case, it is getting increased by a sum of 5 and it is increasing series wise, 0 to, 5 in the first and second series so, it might be increased by 10 in the third series.

In 1st case:

n(14) = n(14) (increasing by 0)

in 2nd case:

O(15) = t(20) (increasing by 5)

In the third case as per the series it will might be increased by 10.

a(1) = k(11)

So, instead of 'a' we are getting 'k' here.

As per the series for the first case it got changed upto 2 letters in the second case by 3 letters so, it can be said that for each case coding the number of interchanged letters are getting increased by 1, so, it might be upto 4 letters in case 3.

If we follow the series, then newly changed number is interchanging by an addition of it term which belongs to its numerical sum with its second greatest factor.

in case 1 there is no change

in the second case fir the last interchanged letter:

O(15) = t(20) (increasing by 5)

Here, the numerical factor o belongs to the 15th and the second greatest factor of 15 is 5.

So, for the third case, we should change 'r', which belongs to 18.

And the second greatest factor of r is 9.

But, if we add 18 and 9 then then we get, 27

But there are 26 letters, so, it will revolve around and it will be the term which is equal to the division of the result by 26.

So, by dividing 27 by 26 we get the remainder as 1.

And the first term is 'a'.

So, instead of 'r' we are getting 'a' here.

And the last letter, that is, 't' will remain unchanged.

So, the code for 'START' is 'WUKAT'.

Answer 2

Step-by-step explanation:

Answer is: BUTRT

MANGO -> break it into two parts MAN + GO

next alphabet of M is N put it in third position

next alphabet of A is B put it in second position

next alphabet of N is O, put it in first position

we will get OBN, add last 2 alphabets as it is in the end and it becomes OBNGO

Similarly, break SCORE into two parts SCO+RE and convert SCO using same logic. We will get PDTRE

Hence, START becomes BUTRT.