Question

in a certain lottery the prize is rs 1 crore and 5000 tickets have been sold what is the expectation of man who holds 10 tickets
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Answer 1

Answer:

1 ticket out of 10,000 tickets can be selected n( S ) = ¹⁰⁰⁰⁰C₁

A/C to question,

10 tickets equal prizes are awarded .so, number of tickets without any prize = 10,000 - 10 = 9,990

so, number of ways in which 1 ticket without prize is obtained n( E ) = ⁹⁹⁹⁰C₁

so, P ( E ) = n ( E )/n( S )

=⁹⁹⁹⁰C₁ / ¹⁰⁰⁰⁰C₁

= 9,990/10,000

= 999/1000

= 0.999

similarly ,

( b ) 2 tickets out of 10,000 can be selected n( S ) = ¹⁰⁰⁰⁰C₂

2 ticket without prize out of 9,990 = ⁹⁹⁹⁰C₂

so, P(E ) = n(E )/n(S )

= ⁹⁹⁹⁰C₂ / ¹⁰⁰⁰⁰C₂

(c ) 10 tickets out of 10,000 can be selected n(S) = ¹⁰⁰⁰⁰C₁₀

10 tickets without prize out of 9,990 can be selected = ⁹⁹⁹⁰C₁₀

so, P( E ) = n(E)/n(S )

= ⁹⁹⁹⁰C₁₀ / ¹⁰⁰⁰⁰C₁₀

Explanation:

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Answer 2

Given :   prize is RS 1 crore and 5000 tickets have been sold.  

To Find :   expectation of a man who holds 10 tickets

Solution:

Assumption: There is a single prize of Rs 1 crore

1 crore = 10000000  

Hence expectation of a man who holds 10 tickets

=  {( number of rickets Hold)/ Total tickets sold  } * Prize money

=  (10/5000) * 10000000

= (1/500) * 10000000

= 20000 Rs

Hence expectation of a man who holds 10 tickets  = 20000 Rs

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