Question

In a certain magazine , 11/27 consists of advertisement and 1/3 of illustration what fraction is readable matter

Answer 1

The fraction of readable matter is $\frac{7}{27}$.

Step-by-step explanation:

Let's consider that the entire content in the magazine equals to 1.

The fraction of advertisement is, $\frac{11}{27}$.

The fraction of illustration is, $\frac{1}{3}$.

Compute the fraction of readable matter as follows:

$Readable\ matter=1-\frac{11}{27}-\frac{1}{3}$

                           $=\frac{27-11-9}{27}$

                           $=\frac{7}{27}$

Thus, the fraction of readable matter is $\frac{7}{27}$.

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