Question

In a certain magazine,11/27 consists of advertisement and 1/3 of illustrations,what fraction is readable matter

Answer 1

$\bf{\underline{\underline{\bigstar\bigstar\: Solution }}}$

$\:\:$

$\footnotesize{ Unreadable \: matter = \dfrac{11}{27} + \dfrac{1}{3} }$

$\footnotesize{\implies Unreadable \: matter = \dfrac{11 + 9}{27} }$

$\footnotesize{\implies Unreadable \: matter = \dfrac{20}{27} }$

$\:\:$

$\rule{200}3$

$\:\:$

$\footnotesize{ readable \: matter = 1 - \dfrac{20}{27} }$

$\footnotesize{\implies readable \: matter = \dfrac{27 - 20}{27} }$

$\footnotesize{\implies readable \: matter = \dfrac{7}{27} }$

Answer 2

Answer:

$\huge {\purple {\fbox {\bigstar {\mathfrak {\red {hello\:mate}}}}}}$

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$\huge {\purple {\fbox {\bigstar {\mathfrak {\red {ur\: question}}}}}}$

$\huge {\mathfrak {\purple {Q.}}}}$ɪɴ ᴀ ᴄᴇʀᴛᴀɪɴ ᴍᴀɢᴀᴢɪɴᴇ,$\frac{11}{27}$ ᴄᴏɴsɪsᴛs ᴏғ ᴀᴅᴠᴇʀᴛɪsᴇᴍᴇɴᴛ ᴀɴᴅ $\frac{1}{3}$ᴏғ ɪʟʟᴜsᴛʀᴀᴛɪᴏɴs,ᴡʜᴀᴛ ғʀᴀᴄᴛɪᴏɴ ɪs ʀᴇᴀᴅᴀʙʟᴇ ᴍᴀᴛᴛᴇʀ

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$\huge {\purple {\fbox {\bigstar {\mathfrak {\red {ur\: ANSWER✓}}}}}}$

$\tt\huge\mathfrak\red{Answer}$

$\tt = \frac{11}{27}+\frac{1}{3}$

$\tt\begin{lgathered}{\implies = \dfrac{11 + 9}{27} }\\\end{lgathered}$

$\tt\begin{lgathered}{\implies = \dfrac{20}{27} }\\\end{lgathered}$

$\tt{\blue{\fbox{\purple{\bigstar{\mathbf{\red{unreadable\:matter=\dfrac{20}{27}}}}}}}}$

$\tt\begin{lgathered}{ = 1 - \dfrac{20}{27} }\\\end{lgathered}$

$\tt\begin{lgathered}{\implies = \dfrac{27 - 20}{27} }\\\end{lgathered}$

$\tt\begin{lgathered}{\implies = \dfrac{7}{27} }\\\end{lgathered}$

$\tt{\blue{\fbox{\purple{\bigstar{\mathbf{\red{readable\:matter= \dfrac{7}{27}}}}}}}}$

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$\huge\mathfrak\red{hope\:it\:helps\:you}$